请教一个dom4j解析xml的问题

我的xml文件内容如下：
<?xml version="1.0" encoding="GB2312"?>
<ConnecToDB>
<Connect DBtype="Oracle" Conntype="driver">
<ClassForname>
oracle.jdbc.driver.OracleDriver
</ClassForname>
<jdbc>jdbc:oracle:thin:@</jdbc>
<host>localhost:</host>
<port>1521:</port>
<SID>ZZX</SID>
<USER>scott</USER>
<PWD>tiger</PWD>
</Connect>
<Connect DBtype="Oracle" Conntype="jdbcodbcbirdge">
<ClassForname>
oracle.jdbc.driver.OracleDriver
</ClassForname>
<jdbc>jdbc:oracle:thin:@</jdbc>
<host>localhost:</host>
<port>1521:</port>
<SID>ZZX</SID>
<USER>scott</USER>
<PWD>tiger</PWD>
</Connect>
</ConnecToDB>
现在如果要求找出 属性DBtype=Oracle，Conntype=driver 的Connect元素，在dom4j中应该怎样实现？

http://www-128.ibm.com/developerworks/cn/xml/x-dom4j.html

我看了，上面没有能够解决我所提出的问题的示例代码啊

package test.xml.dom4j.csdn;

import java.io.File;
import java.util.Iterator;

import org.dom4j.Attribute;
import org.dom4j.Document;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;


public class Test {

/**
* 通过DOM4J读取xml文档
* @throws Exception
*/
public static void readXML() throws Exception
{
SAXReader reader = new SAXReader();
//文件名换成你的即可.
String fileName ="D:\\IJ310\\BeginJava\\workspace\\test.xml.1\\src\\test\\xml\\dom\\csdn\\test.xml";
Document doc = reader.read(new File(fileName));

Element root = doc.getRootElement();
Iterator iter = root.elementIterator("Connect");
while (iter.hasNext())
{
Element ele1 = (Element)iter.next();
Attribute attr1 = ele1.attribute("DBtype");
Attribute attr2 = ele1.attribute("Conntype");
String str1 = attr1.getText().trim();
String str2 = attr2.getText().trim();
if (str1.equalsIgnoreCase("Oracle") && str2.equalsIgnoreCase("driver"))
{
Element ele2 = ele1.element("ClassForname");
System.out.println(ele2.getText());
}


}

}
/**
* 测试入口
* @param args
*/
public static void main(String[] args)
{
try
{
readXML();

}
catch(Exception ex)
{
ex.printStackTrace();
}
}

}

List bblist = document.selectNodes("//Connect[@DBtype='Oracle'] | //Connect[@Conntype='driver'] ");

这样取。。。

ysycrazy(风中狂) ( ) 信誉：100 Blog
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